Answer to Question #158487 in General Chemistry for Hailee Stokes

Question #158487

A balloon at the top of Mount Logan occupies a volume of 775mL at a temperature of -28°C and a pressure of 92.5kPa. What is the pressure at the bottom of the mountain if the same balloon has a volume of 825mL at a temperature of 15°C? 


1
Expert's answer
2021-01-26T03:23:26-0500

-28oC = 273 - 28 = 245 K

15oC = 273 + 15 = 288 K

According to the combined gas law,


p1V1T1=p2V2T2\frac{p_1V_1}{T_1}=\frac{p_2V_2}{T_2}


Therefore,


p2=p1V1T2T1V2=92.5kPa×775mL×288K245K×825mL=102kPap_2=\frac{p_1V_1T_2}{T_1V_2}=\frac{92.5kPa\times775mL\times288K}{245K\times825mL}=102kPa


Answer: 102 kPa


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