Answer to Question #158472 in General Chemistry for Maria

Question

NH₄Cl + Ca(OH)₂ --> NH₃ + H₂O + CaCl₂

If 3.5 moles Ca(OH)₂ are added to 380ml 1.3M NH₄Cl how many moles of Ca(OH)₂ will be left over?

Answer 1

$$2NH4Cl+Ca(OH)2\to2NH3+2H2O+CaCl$$

1.3/2=n/1

n=1.3/2=0.65 mol

$$\Delta n (Ca(OH)2)=3.5-0.65=2.85 mol$$

So 2.85 mol Ca(OH)2 will be left over.