Question

6Na + Fe2O3 --> 3Na2O + 2Fe If you are provided 100g Na and 100g of Fe3O2

Answer 1

6Na +  Fe₂O₃ --> 3Na₂O + 2Fe

$n(Na)=\frac{m}{M}=\frac{100}{22.9898}=4.35$

$n(Fe2O3)=\frac{m}{M}=\frac{100}{159.691}=0.63$

 Fe2O3 - limiting reagent

$m (Na2O)=n\times M=0.63\times61.979=38.81$

$m (Fe)=n\times M=0.63\times55.847=35.18$