AgNO3 +CuCl2 --> AgCl + Cu(NO3)3
If 1.5l of 0.8M AgNO3 is added to 1.2l of 0.6M CuCl2 what is the concentration of AgCl in the new solution?
C(AgCl)=C(AgNO3)=0.8 M
m= M×n=143.5×0.8=114.5 g
"\\rho =114.5\/(1.2+1.5)=42.5 g\/L"
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