Question

AgNO₃ +CuCl₂ --> AgCl + Cu(NO₃)₃

If 1.5l of 0.8M AgNO₃ is added to 1.2l of 0.6M CuCl₂ what is the concentration of AgCl in the new solution?

Answer 1

C(AgCl)=C(AgNO3)=0.8 M

m= M×n=143.5×0.8=114.5 g

$\rho =114.5/(1.2+1.5)=42.5 g/L$