MnO2 + Al --> Mn + Al2O3
If 26.5g Al are added to 150ml 0.8M Mn what will be the concentration of Mn produced?
V1 = 26.5g = 26.5ml ,M1 = ? M2 = 0.8M ,V2 = 150ml
M1V1 = M2V2
M1 × 26.5ml = 0.8M × 150 ml
M1 = 4.52M
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