Volume (v)=3500mL=3.5Lconcentration (c)=0.25mol/L
Using the formula,
number of moles=c×V=0.25×3.5=0.875moles
note that the molar mass of glucose is 180 g/mol
mass =number of moles×molar mass=0.875×180=157.5g
Therefore, 157.5g of glucose, C₆H₁₂O₆, will be needed to dissolve in water.
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