You need to make 3500 mL of a glucose solution with a concentration of 0.25 mol/L. What mass of glucose, C₆H₁₂O₆, will you need to dissolve in water?
"Volume\\ (v) = 3500mL = 3.5L\\\\ concentration\\ (c) = 0.25mol\/L"
Using the formula,
"\\begin{aligned}\n\\textsf{number of moles} &= c \u00d7V\\\\\n&= 0.25\u00d7 3.5\\\\\n&= 0.875 moles\n\\end{aligned}"
note that the molar mass of glucose is 180 g/mol
"\\begin{aligned}\\textsf{mass } &= \\textsf{number of moles}\u00d7 \\textsf{molar mass}\\\\\n&= 0.875\u00d7 180 \\\\\n&= 157.5g\n\\end{aligned}"
Therefore, 157.5g of glucose, C₆H₁₂O₆, will be needed to dissolve in water.
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