Question #155453

You need to make 3500 mL of a glucose solution with a concentration of 0.25 mol/L. What mass of glucose, C₆H₁₂O₆, will you need to dissolve in water?



1
Expert's answer
2021-01-15T06:31:58-0500

Volume (v)=3500mL=3.5Lconcentration (c)=0.25mol/LVolume\ (v) = 3500mL = 3.5L\\ concentration\ (c) = 0.25mol/L


Using the formula,

number of moles=c×V=0.25×3.5=0.875moles\begin{aligned} \textsf{number of moles} &= c ×V\\ &= 0.25× 3.5\\ &= 0.875 moles \end{aligned}


note that the molar mass of glucose is 180 g/mol

mass =number of moles×molar mass=0.875×180=157.5g\begin{aligned}\textsf{mass } &= \textsf{number of moles}× \textsf{molar mass}\\ &= 0.875× 180 \\ &= 157.5g \end{aligned}



Therefore, 157.5g of glucose, C₆H₁₂O₆, will be needed to dissolve in water.


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