Question

1. How many particles are in 125 moles of Sodium Acetate (NaC2H3O2)

Answer 1

A mole of Sodium Acetate contains 6.02×10²³ molecules.

Proportion:

1 mol - 6.02×10²³ molecules

125 mol - x

$x = \frac{125 \times 6.02 \times 10^{23}}{1}= 7.52 \times 10^{25} \;molecules$

Answer: 7.52×10²⁵ molecules