A gas at a constant temperature occupies a volume of 2.10 L and exerts a pressure of 98.3 kPa. What volume will the gas occupy at a pressure of 115.5 kPa?
Using the boyle's rule
V1P1=V2P2
V1=2.1 V2=? P1=98.3 P2=115.5
V2=V1P1/P2
V2=2.1×98.3/115.5
V2=1.79L
Comments
Leave a comment