Answer to Question #153008 in General Chemistry for Joy

Question

The concentration of X²⁻ in a saturated solution of A₂X₃ is 9.62 x 10⁻¹¹ mg/L. What is the Ksp of
A₂X₃ if the MM of X is 32.06 g/mol?

Answer 1

A₂X₃ = 2 A³⁺ + 3 X^2-

Ksp = [A³⁺]² × [X^2-]³

since concentration of both the ions are same.

[X^2-] = (9.62×10^-14 g/L)/(32.06 g/mol)

[X^2-] = 3 × 10^-15 M

so Ksp = (3×10^-15)⁵ = 2.43 × 10^-73