Answer to Question #153007 in General Chemistry for Joy

Question #153007
Consider the equilibrium reaction: YZ2(s) ⇌ Y2+(aq) + 2Z-(aq). What is the molar solubility of YZ₂ (Ksp= 4.0 x 10⁻¹¹) at 25⁰C in a 0.03 M AZ₂ solution? Assume that AZ₂ is a strong electrolyte.
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Expert's answer
2020-12-29T02:43:24-0500

Because the stoichiometry of the reaction is four NH3 to one Cu2+, the amount of NH3 required to react completely with the Cu2+ is 4(0.0846) = 0.338 M. The concentration of ammonia after complete reaction is 1.00 M − 0.338 M = 0.66 M. These results are summarized in the first two lines of the following table. Because the equilibrium constant for the reaction is large (2.1 × 1013), the equilibrium will lie far to the right. Thus we will assume that the formation of [Cu(NH3)4]2+ in the first step is complete and allow some of it to dissociate into Cu2+ and NH3 until equilibrium has been reached. If we define x as the amount of Cu2+ produced by the dissociation reaction, then the stoichiometry of the reaction tells us that the change in the concentration of [Cu(NH3)4]2+ is −x, and the change in the concentration of ammonia is +4x, as indicated in the table. The final concentrations of all species (in the bottom row of the table) are the sums of the concentrations after complete reaction and the changes in concentrations.


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