Answer to Question #151925 in General Chemistry for Kylie Spuhler

General Chemistry

Question #151925

How much heat is required to heat 50.0 g of water from 25.0 ̊C to 75.0 ̊C?

Expert's answer

q = mC∆T

∆T = (75-25) = 50°C

m = 50g

C = 4.18 J/g/°C

q = 50× 4.18× 50

q = 10450 J which is equal to 10.45KJ

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