Answer to Question #151913 in General Chemistry for Destanie

Question #151913
What number of moles of O2 is needed to produce 14.2 grams of P4O from P
1
Expert's answer
2020-12-18T08:46:43-0500

Molar mass of P4O10 = 283.886 g/mol


4P + 5O2 = P4O10

From the balanced chemical reaction

We get that to produce 1 mole of P4O10, 5 mole of O2 needed

I.e for 283.886 g of P4O10, 5 mole of O2 needed

For 1 g of P4O10, (5/283.886) mole of O2 needed

For 14.2 g of P4O10, (5×14.2/283.886) mole of O2 needed

= 0.25 mole


Hence, 0.25 mole of O2 is needed to produce 14.2 grams of P4O10 from P.




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