Question #148985

a ) Describe the transformations to the graph of y = x² to obtain y = -2 ( x + 5 )²- 3 .

b ) Graph y = x² . Then apply the transformations in part ( a ) to graph y = -2 ( x + 5 ) ² - 3 .

c ) Determine the domain and range of this transformed function .


1
Expert's answer
2020-12-07T08:00:48-0500

a) Consider the transformed function y=2(x+5)23y=-2(x+5)^2-3 from the parent function y=x2y=x^2


i) Multiply x2x^2 by 2 to obtain h(x)=2x2h(x)=2x^2 in order to stretch the curve vertically as shown in the figure below:





ii) Multiply h(x)=2x2h(x)=2x^2 by 1-1 to obtain the function g(x)=2x2g(x)=-2x^2 in order to reflect the curve about xx -axis as shown in the figure below:




iii) Shift left by 5 units in order to transformed the function l(x)=2(x+5)2l(x)=-2(x+5)^2 as shown in the figure below:




iv) Shift vertically down by 3 units to obtain the final transformed function y=2(x+5)23y=-2(x+5)^2-3 as shown in the figure below:





b) The sketch of the graph in part (a) is as shown in the figure below:





c) Since, the function y=2(x+5)23y=-2(x+5)^2-3 is defined for all xx in R2R^2 ,


So, the domain of the function is (,)(-\infin,\infin)


The graph of the function y=2(x+5)23y=-2(x+5)^2-3 opens downward, so the maximum value is 3-3 .


Therefore, the range of the function is (,3](-\infin,-3] .

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