Ca(NO3)2 "\\rightarrow" Ca2+ + 2NO3-
moles of Ca(NO3)2 = "\\frac{7.72\u00d7 10^{-4}}{164.08}"
moles of Ca(NO3)2 = 4.7× 10-6 moles
Total number of ions = 3
so according to stoichiometry total concentration of ions = 3 × 4.7× 10-6 moles
which is equal to 14.1× 10-6 moles
Comments
Leave a comment