Ca(NO3)2 →\rightarrow→ Ca2+ + 2NO3-
moles of Ca(NO3)2 = 7.72×10−4164.08\frac{7.72× 10^{-4}}{164.08}164.087.72×10−4
moles of Ca(NO3)2 = 4.7× 10-6 moles
Total number of ions = 3
so according to stoichiometry total concentration of ions = 3 × 4.7× 10-6 moles
which is equal to 14.1× 10-6 moles
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