Answer to Question #148759 in General Chemistry for Nwosu Tochi

Question

Solution A contain an unknown concentration of sulphuric acid. Solution B contains 15g of NaOH. Calculate the concentration of NaOH

Answer 1

Your question does not have enough information but this is how you solve a question like this.

A reacts with B to form a product, but since we know the constituents of A and B, the chemical reaction is therefore;

$H_2SO_4 + 2NaOH \to Na_2SO_4 + 2H_2O$

Number of moles of NaOH = 15g/40g = 0.375 moles

Since 1 mole of H2SO4 reacts with 2 moles of NaOH

Number of moles of H2SO4 is therefore 0.375/2 = 0.1875 moles.

Let's say the volume of NaOH is 50mL,

The concentration of the NaOH solution is therefore 0.375/50 × 1000 which is equal to 7.5M

Therefore the concentration of NaOH is 7.5M if the solution has a volume of 50mL.

And if you want to calculate the concentration of H2SO4 solution, it will be 0.1875/volume of H2SO4 (L)