Answer to Question #148802 in General Chemistry for Bria

Question #148802
Calculate the number of grams of solute in 388.2 mL of 0.263 M calcium acetate
1
Expert's answer
2020-12-06T13:37:38-0500

First we need to find the moles of solute in the solution;

We have 0.263 moles in 1000mL of solution,

How many moles would be in the 388.2mL of solution?


Use the formula


Molesofsolute=Molarity(M)xVolume(mL)1000mLMoles of solute=\dfrac{Molarity(M) x Volume(mL)}{1000mL}


=0.263molx388.3mL1000mL=\dfrac{0.263mol x 388.3mL}{1000mL}


=0.1020966mol= 0.1020966mol of Calcium acetate


Secondly, Calculate mass of the solute;


Massofsolute=MolesxMolarmassMass of solute = Moles x Molar mass


Molar mass of Ca(C2H3O2)2 = 158.17g/mol


Mass = 0.1020966 mol x 158.17g/mol

= 16.149g

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