First we need to find the moles of solute in the solution;
We have 0.263 moles in 1000mL of solution,
How many moles would be in the 388.2mL of solution?
Use the formula
"Moles of solute=\\dfrac{Molarity(M) x Volume(mL)}{1000mL}"
"=\\dfrac{0.263mol x 388.3mL}{1000mL}"
"= 0.1020966mol" of Calcium acetate
Secondly, Calculate mass of the solute;
"Mass of solute = Moles x Molar mass"
Molar mass of Ca(C2H3O2)2 = 158.17g/mol
Mass = 0.1020966 mol x 158.17g/mol
= 16.149g
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