Answer to Question #147784 in General Chemistry for Lsae

Question #147784

How many grams of water are produced by burning 96 grams of H2 and the same amount of O2.

Expert's answer

2H₂+ O₂ = 2H₂O

O₂ is the limiting reagent

O₂ = 2H₂O

16×2 g O₂ = 2 × 18 g H₂O

1g O₂ = 2×18 / 32 gH₂O

96g O₂ = 2×18 ×96 / 32 g H₂O

= 108g H₂O

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