Answer to Question #147765 in General Chemistry for Jordyn

Question

An initial volume of 3.7 L of a gas are maintained at constant pressure while being cooled from 95 ºC to 22 ºC. What is the new volume of the gas?

Answer 1

According to the law of volumes:

$\frac{V_1} {T_1} = \frac{V_2} {T_2}$ for the same amount of a gas at constant pressure.

$V_{new} = V_{orginal} * \frac{T(22\ ^0C)}{T(95\ ^0C)};$

$T(t) = (273.15 + t) \ K \ ;$

$T(22\ ^0C) = (273.15 + 22) \ K = 295.15\ K;$

$T(95\ ^0C) = (273.15 + 95) \ K = 368.15\ K;$

$V_{new} = 3.7\ L * \frac{295.15\ K}{368.15\ K}\approx 2.966\ L;$

Answer: $V_{new} = 2.966\ L$