You are given the OH concentration, so you can solve for the pOH.
pOH+pH=14pOH=−log(OH)=−log(2.5×10−7)=6.60pH=14−pOH=14−6.607.40pOH + pH= 14\newline pOH= -log(OH)=-log(2.5×10^-7)=6.60\newline pH=14-pOH\newline =14-6.60\newline 7.40pOH+pH=14pOH=−log(OH)=−log(2.5×10−7)=6.60pH=14−pOH=14−6.607.40
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