From Charles law expression of an ideal gas;
V1T1V_1\over T_1T1V1 === V2T2V_2\over T_2T2V2
V1=14.5cm3V_1=14.5cm^3V1=14.5cm3
V2=60.0cm3V_2=60.0cm^3V2=60.0cm3
T1=23°CT_1=23°CT1=23°C
T2=unknownT_2=unknownT2=unknown
∴\therefore∴ T2=T_2=T2= V2×T1V1V_2\times T_1\over V_1V1V2×T1
T2=T_2=T2= 60.0cm3×23.0°C14.5cm360.0cm^3\times 23.0°C\over 14.5cm^314.5cm360.0cm3×23.0°C
T1=95.17°CT_1=95.17°CT1=95.17°C
The variation in temperature=95.17°C−14.5°C=80.67°C=95.17°C-14.5°C=80.67°C=95.17°C−14.5°C=80.67°C
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments