Calculate the hydronium concentration of a certain ionization reaction where the hydroxide concentration is determined to be 2.7 x 10-5 M. Identify if the solution is acidic, basic, or neutral.
pOH= -log(OH-)
=-log(2.7×10^-5)
=4.569
pH= 14-pOH
pH= 14-4.569
=9.431
[H30+]= antilog(-pH)
=antilog(-9.431)
=3.707×10^-10 M
The solution is basic since pH is 9.431 and the concentration of hydroxide ions is more than that of hydronium.
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