Answer to Question #146502 in General Chemistry for Rex

Question

How much heat (in joules) is used to heat a 52.38 gram sample of iron from 10.83 degrees Celsius to 100.00 degrees Celsius if the specific heat of Fe is 0.450 J/g*C? Record your answer to 2 decimal spaces.

Answer 1

Specific heat formula

Q = mCΔT

Q = heat energy = ?

m = mass = 52.38g

C = specific heat = 0.450J/g*C

ΔT = change in temperature = 100.00 - 10.38 = 89.17 celcius

Q = mCΔT

Q = 52.38 g × 0.450J/g*C × 89.17 celcius

Q = 2101.82 Joules