2NaOH+Mg(NO3)2=2NaNO3+Mg(OH)2
0.5 x 0.12 = 0.06 mol of NaOH
0.5 x 0.1 = 0.05 mol of Mg(NO3)2.
0.06/2 =0.03
0.05 - 0.03 = 0.02 mol of Mg(NO3)2
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