Answer to Question #145993 in General Chemistry for Loz

Question

A solution is made by mixing 500.0ml of 0.12M NaOH soulution with 500mL of 0.1M Mg(NO3)2

Ksp for Mg =1.8 x10^-11

What will Mg and Oh^- be after mixing?

Answer 1

500.0ml of 0.12M NaOH 

500mL of 0.1M Mg(NO3)2

Ksp for Mg =1.8 x10^-11

500 ml = 0.12m

1000ml = ? ((1000)(0.12))/ (500)

= 0.24moles

500ml = 0.1m

1000ml = ((1000)(0.1))/500

= 0.2 moles

Therefore

(0.2)(0.24)(1.8 x10^-11)

= 8.64^-13