Answer to Question #145982 in General Chemistry for Flexus

Question #145982
Consider the reaction: 2HI(g) ⇋ H2(g) + I2(g). The equilibrium concentrations for these reaction at
445℃ are [HI] = 2.0 M, [H2] = 0.50 M, [I2] = 0.10 M. Calculate the equilibrium constant (Kc).
1
Expert's answer
2020-11-23T07:33:31-0500

The reaction given,

2HI(g) ⇋ H2(g) + I2(g)

Equilibrium constant,

Kc = [H2][I2]/[HI]2


Given,

At temperature = 445℃

[HI] = 2.0 M

[H2] = 0.50 M

[I2] = 0.10 M

So,

Kc = [H2][I2]/[HI]2

Or, Kc = 0.50×0.10/(2.0)2

Or, Kc = 0.0125


Hence, Equilibrium constant = 0.0125

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