T = 100oC = 373.15 K
R = 8.314 J/mol-K
M (CO2) = 0.04401 kg/mol
"V_{rms}=\\sqrt{\\frac{3RT}{M}}=\\sqrt{\\frac{3\\times8.314J\/mol\\cdot{K}\\times373.15K}{0.04401kg\/mol}}=459.9m\/s"
Answer: 459.9 m/s
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