Cu(NO3)2 + SrCl2 → CuCl2 + Sr(NO3)2
M(Cu(NO3)2) = 187.56 g/mol
n(Cu(NO3)2) "= \\frac{5.184}{187.56} = 0.0276 \\;mol"
n(SrCl2) = n(Cu(NO3)2) = 0.0276 mol
M(SrCl2) = 158.53 g/mol
m(SrCl2) "= 0.0276 \\times 158.53 = 4.38 \\;g"
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