Answer to Question #145801 in General Chemistry for jayden

Question

What mass of ammonium phosphate is produced by the reaction of 7.00g of phosphoric acid?

Answer 1

Triammonium phosphate can be prepared in the laboratory by treating 85% phosphoric acid with 30% ammonia solution:

H₃PO₄ + 3 NH₃ → (NH₄)₃PO₄.

The solid, which has the odor of ammonia, is readily soluble in water. The salt converts to diammonium hydrogen phosphate (NH₄)₂HPO₄.

H₃PO₄ + 3 NH₃ → (NH₄)₃PO₄.

Mole ratio = 1 :3: 1

Therefore

1 mole of H₃PO₄ = 1 mole (NH₄)₃PO₄

7g = 1 m

? = 1m = ((7)(1))/(1)

= 7 g