Question #145725

Calculate the number of moles in 15.36g of lead (II) nitrate, Pb(NO3)2.


1
Expert's answer
2020-11-22T11:26:57-0500

1 mole of Pb(NO3)2→331.2098grams→15.36grams=15.36÷331.2098=0.046molesPb(NO_3)_2\to331.2098 grams\newline \to15.36 grams=\newline 15.36÷331.2098\newline = 0.046 moles


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