Question

CF2Cl2 + 2Na2C2O4 = 2NaF + 2NaCl + C + 4CO2

What mass of NaCl in grams will be form if 2.35 mol of CF2Cl2 are heated and allowed to react completely with Na2C2O4?

Answer 1

n(NaCl) = 2n(CF₂Cl₂)

n(NaCl) $= 2 \times 2.35 = 4.7 \;mol$

M(NaCl) = 58.44 g/mol

$m = n \times M$

m(NaCl) $= 4.7 \times 58.44 = 272.67 \;g$