Answer to Question #144972 in General Chemistry for ken

Question

K2S2O3 + 4Cl2 + 5H2O = 2KHSO4 +8HCl

Assume that 38.85 g of K2S2O3 is used in the process of removing excess chlorine. How many moles of HCl will be produce?

Answer 1

According to stoichiometry

1 mole of K₂S₂O₃ will produce 8 mole of HCl

38.5 g of K₂S₂O₃ = 0.20 moles

So it will produce 1.6 moles of HCl