Answer to Question #144900 in General Chemistry for Vic

General Chemistry

Question #144900

How many milliliters of 11.5 M HCl(aq) are needed to prepare 405.0 mL of 1.00 M HCl(aq)

Expert's answer

We apply the relationship;

M₁V₁ = M₂V₂(Where M1= 11.5M, M2= 1.00M, V2 = 405.0mL, V1=?)

$V1 = \dfrac{M2V2}{M1}$

$=\dfrac{1.00M x 405.0mL}{11.5M} = 35.217mL$

Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. 29. A solution that contains 800 mg/dL serum is diluted 1⁄2, then 1⁄4, then 1/8, and then again
2. An “ice calorimeter” can be used to determine the specific heat capacity of a metal. A piece of
3. determine the total volume of gas produced at stp when 1g of silver nitrate is heated.
4. Consider the following equilibrium process:2I(g)<=>I2(g)Predict the direction of the shift in
5. Consider three photons of light A,B, and C. Show with calculations the relative order of the energie
6. Assess the spontaneity of the following reaction using ΔSsys and ΔSsurr: 3 X2 (g) + R (l) →
7. Powdered zinc metal reacts with sulphur (S8) when heated to produce zinc sulphide.