Answer to Question #143282 in General Chemistry for Wisdom ugoala

Question

In an equilibrium reaction between gases Q2 and R2 to form QR, the energy content of the reactants is 100kg and that of the product is 54kg the energy content of the activated example is 210kg.
1. Draw an energy profile diagram for the reaction
2. Determine the activation energy of the reaction.
3. Determine the enthalpy change for the reaction
Write a balanced equation for the reaction

Answer 1

1.

2. $\Delta H°=\sum \Delta H°_{(reactants)}-\Delta H°_{(products)}$

$\Delta H°_{(reaction)}=(100kJ+(54kJ)-2(210)$

$=-266kJ$

3. $\Delta H=\sum \Delta H_ {(bonds broken in reactants)}-\sum \Delta H_{(Bonds made in products)}$

$Delta H°_{(reaction)}=(100kJ+(54kJ)-(210)=-56$

A balanced equation for the reaction is;

$Q_2+R_2\to 2QR$