Answer to Question #142056 in General Chemistry for karlisa valenica

Question

 How many grams of Cu²⁺ are present in 2.94 grams of copper(II) phosphate

Answer 1

Cu₃(PO₄)₂(s) ⇌ 3 Cu²⁺(aq) + 2 PO₄^3–(aq)

Cu₃(PO₄)₂ gives 3 Cu²⁺

[(63.55×3)+(31×2)+(16×8)]g of Cu₃(PO₄)₂ gives 3× 63.55g Cu²⁺

380.65g Cu₃(PO₄)₂ gives 190.65g Cu²⁺

1g Cu₃(PO₄)₂ gives 190.65/380.65g Cu²⁺

2.94g Cu₃(PO₄)₂ will give [190/380.65]× 2.94g Cu²⁺

2.94g Cu₃(PO₄)₂ will give 1.473g Cu²⁺