Question

How many moles of sulfuric acid are required to neutralize 10ml of 1.65M ammonia?

Answer 1

The reaction equation is

H₂SO₄ + 2NH₄OH --> (NH₄)₂SO₄ + 2H₂O

10 mL = 0.010 L

$n_{NH_4OH}=0.010L\times1.65M=0.0165mol$

According to the equation, 1 mole of H₂SO₄ is required to neutralize 2 moles of ammonia. Therefore, $n_{H_2SO_4}=\frac{0.0165mol}{2}=0.00825mol$

Answer: 0.00825 mol