The reaction equation is
H2SO4 + 2NH4OH --> (NH4)2SO4 + 2H2O
10 mL = 0.010 L
"n_{NH_4OH}=0.010L\\times1.65M=0.0165mol"
According to the equation, 1 mole of H2SO4 is required to neutralize 2 moles of ammonia. Therefore, "n_{H_2SO_4}=\\frac{0.0165mol}{2}=0.00825mol"
Answer: 0.00825 mol
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