Question

calculate the volume (in ml) of 2.25 M HNO3 solution required to react with 24.2 ml of 3.50 M NaOH solution

Answer 1

Solution:

NaOH + HNO₃ → NaNO₃ + H₂O

Mole ratio  NaOH : HNO₃ = 1 : 1

Millimoles of NaOH reacted = (3.50 $\tfrac{mmol}{ml}$) × (24.2 $ml$ ) = 84.7 $mmol$

Millimoles of HNO₃ required = 84.7 $mmol$

Volume of HNO₃ required = $\dfrac{84.7mmol}{2.25 \tfrac{mmol}{ml} }$ = 37.6 $ml$

Answer:

37.6 $ml$ volume