NaOH + HNO₃ → NaNO₃ + H₂O
Mole ratio NaOH : HNO₃ = 1 : 1
Millimoles of NaOH reacted = (3.50 "\\tfrac{mmol}{ml}") × (24.2 "ml" ) = 84.7 "mmol"
Millimoles of HNO₃ required = 84.7 "mmol"
Volume of HNO₃ required = "\\dfrac{84.7mmol}{2.25 \\tfrac{mmol}{ml}\t}" = 37.6 "ml"
37.6 "ml" volume
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