At first, the equation should be balanced:
6CO2+6H2O+light=C6H12O6+6O2.
Volume of oxygen may be found from a proportion:
V(O2)=m(H2O)×6×Vm/6×M(H2O)=m(H2O)×Vm/M(H2O),
where Vm is a molar volume and M(H2O) is a molar mass of water.
V(O2)=125.67×22.4/18=156.39(L)
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