Answer to Question #138768 in General Chemistry for Josephine Beks

Question

If 10mg of benzene is subjects to combustion analysis, what mass of CO2 and H2O will be produced?

Answer 1

balanced equation

2C₆H_{6       (g)}+ 15 O_{2      (g)}                 12 CO2 (g ) +      6 H2O  (g)

moles of benzene

2(12*6+ 1*6)=156

1mole=156g

   ? = 10g

there for

(1*10/156)=0.0641

Mole ratio

2:15:12:6

moles of carbondioxide

  moles= ( 0.0641*12/2)=0.3846 mole

mass=moles *molar mass

       0.3844*44= 16.9136g

moles of H20

0.0641*6/2= 0.1923moles

mass=moles *moler mass

          0.1923*18

        =3.4614 g