We use the ideal gas equation.......PV=nRT
n=PV/RT
=(1.5 atm)(8.56L)/(0.082 lit-atmp/Kelvin mole)(273 K)
n =0.573 mole
Moles H2 is=0.573 moles
Atomic mass of H is=1.00784 amu
Mass of H2 is =(1.00784 amu)(0.573 moles)
Hence mass of H2 is =0.577g present in the gas sample
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