Answer to Question #137890 in General Chemistry for Edward Calamigan

Question

The solubility of potassium nitrate at 20 °C is 250g/L. How many grams of potassium nitrate is needed to be solved in 150mL of water?

Answer 1

Solution:

1 L = 1000 mL

If solubility of KNO₃ is 250 grams in 1L of water, then calculate mass of KNO₃ in 150 mL of water

mass KNO₃ = $250g/1 × 150ml/1000ml$ = 37.5 g KNO₃

Answer: 37.5 grams of KNO₃ are needed to solve in 150 mL of water