Question

Calculate the number of grams of O2 required for the complete combustion of 1.50kg of C2H2:2C2H2+—> 4CO2+2H2O

Answer 1

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

m(C₂H₂) = 1.50 kg = 1.50*10³ g.

Let's make a proportion according to the reaction equation:

1.50*10³ g C₂H₂ — x g O₂ ;

2*26 g C₂H₂ — 5*16 g O_{2 .}

$x = \frac{1.50*10^3*5*16}{2*26} = 2308 (g) \approx\ 2310\ g\ —\ m (O2)$