Question

a gaseous mixture contains the three noble gases helium, argon, and krypton. the total pressure exerted by the mixture is 1.57 atm and the partial pressures of he and ar are 0.33 atm and 0.39 atm repectively what is the partial pressure of the kr in the mixture

Answer 1

The total pressure exerted by the mixture is 1.57 atm

The partial pressures of He 0.33 atm

The partial pressure of Ar 0.39 atm

Therefore:

1.57atm = (0.33+ 0.39+ Kr)

1.57atm. = 0.72 + Kr

Kr. = ( 1.57 - 0.72)

Kr = 0.85 atm