Answer to Question #137522 in General Chemistry for Maria

Question

How many grams are 4.37 * 10^21 atoms of aluminum?

Answer 1

Solution:

The molar mass of aluminum is 26.9815 g/mol.

So it is the mass of 1 mole of aluminum (Al) i.e. 6.02⋅10²³ atoms of Al.

Hence the mass of 4.37⋅10²¹ atoms of Al will be:

(26.9815 g/mol) × (4.37⋅10²¹ / 6.02⋅10²³) = 0.196 g

Answer: 0.196 grams of Al correspond to 4.37⋅10²¹ atoms of Al.