Molicular formula of FERRIC CHLORIDE is = FeCl3
Molicular weight of FeCl3
(Atomic mass of Fe + atomic mass of chlorine ×3)
= (56+ 35.5×2)
= 56+ 71
= 127 g/mol
Molicular formula of FERRIC SULFATE is = Fe2(SO4)3
Molicular weight of Fe2(SO4)3
(Atomic mass of Fe + atomic mass of chlorine ×3)
= 56×2+(32×3+12×16
= 400 g/mol
Hence,
If only FERRIC CHLORIDE is available in the market instead of FERRIC SULFATE, I need to purchase 127g FERRIC CHLORIDE for every 400 g of FERRIC SULFATE.
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