Answer to Question #137366 in General Chemistry for Nithusha

Question

student A prepared 0.044 M concentration of the stock sodium salicylate solution and using a Mohr pipet transferred 5ml of the 0.044 M sodium salicylate stock solution into a 100 ml volumetric flask labelled as sample 1. the solution was diluted to the 100 ml mark with the acidified 0.02 M iron 3 chloride solution. what is the concentration of iron 3 salicylate complex in the sample 1 flask.

Answer 1

Equation of reaction

3C₇H₅NaO₃ +FeCl₃----------->C₂₁H₁₅FeO₉+3NaCl

C₇H₅NaO₃ : C₂₁H₁₅FeO₉ mole ratio 3:1

Moles of C₇H₅NaO₃ =(0.044÷1000)×5=0.00022

Using the mole ratio, the moles for C₂₁H₁₅FeO₉ will be (0.00022÷3)×1=0.000073moles

This is present in 100ml. To find concentration in 1L,

(0.000073÷100)×1000=0.00073

=7.3×10^-4mols L^-1