Answer to Question #137363 in General Chemistry for Eboni

Question

A car is 35.3 m down from the lizard driving toward it at a speed of 30.5 m/s. How long will it take the car to drive 35.3 m? Round to the tenth of a second

Answer 1

Distance $s= 35.3\ m$

Velocity of car $v= 30.5\ m/s$

Time t $= \frac{s}{v}=\frac{35.3}{30.5}=1.157\ s$ $\approx 1.2\ s$