Answer to Question #137340 in General Chemistry for Nicole Stone

Question

If 30.0 mL of 5.0 M HCl is used to make a 500.0 mL aqueous solution, what is the molarity of the dilute solution?

Answer 1

V1=30mL=0.03L

C1(HCl)=5 M

V2=500mL=0.5L

C2(HCl)-?

n(HCl)= V1*C1(HCl)=0.03*5=0.15(mol)

C2(HCl)=n(HCl)/V2=0.15/0.5=3 M

Answer: 3 M