A 5.44 g
mixture contains both lithium fluoride, LiF,
and potassium fluoride, KF.
If the mixture contains 3.48 g
fluorine, what is the mass of the KF
in the mixture?
1
Expert's answer
2020-10-06T09:36:03-0400
system of equations:
58*x+26*y=5,44g
(x+y)*19=3, 48
where is x- chemical amount of KF and y is chemical amount of LiF
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