Question

If 250 kJ of energy are absorbed in the following reaction, how many moles of CO₂ reacted:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂ ΔH=2803 kJ

Answer 1

Let's make a proportion according to the reaction equation:

n = 6 moles of CO₂ — ΔH=2803 kJ;

n₁= x moles of CO₂ — ΔH₁=250 kJ.

$$n1 = \frac{n*ΔH1}{ΔH}; n1 = \frac{6*250}{2803} = 0.5351 kJ.$$