Solution:
For redox reaction
M1 × n1 × V1 = M2 × n2 × V2
M - molarity
M Fe2+ × n Fe2+ × V Fe2+ = M KBrO3 × n KBrO3 × V KBrO3
For the following reaction calculate molarity M Fe2+
n of KBrO3 = 1; n of Fe 2+ = 1/6
M Fe 2+ = M KBrO3 × n KBrO3 × V KBrO3 / n Fe2+ × V Fe2+ = 0.113×1×35.50 / 1/6×13.0 = 1.85M
Answer: Molarity of the Fe2+ solution is 1.85M.
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